Find the layer with the smallest enclosing node in language_scope_at
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6 changed files with 151 additions and 69 deletions
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@ -2145,23 +2145,27 @@ impl BufferSnapshot {
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pub fn language_scope_at<D: ToOffset>(&self, position: D) -> Option<LanguageScope> {
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let offset = position.to_offset(self);
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let mut range = 0..self.len();
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let mut scope = self.language.clone().map(|language| LanguageScope {
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language,
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override_id: None,
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});
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if let Some(layer_info) = self
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.syntax
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.layers_for_range(offset..offset, &self.text)
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.filter(|l| l.node().end_byte() > offset)
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.last()
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{
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Some(LanguageScope {
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language: layer_info.language.clone(),
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override_id: layer_info.override_id(offset, &self.text),
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})
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} else {
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self.language.clone().map(|language| LanguageScope {
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language,
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override_id: None,
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})
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// Use the layer that has the smallest node intersecting the given point.
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for layer in self.syntax.layers_for_range(offset..offset, &self.text) {
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let mut cursor = layer.node().walk();
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while cursor.goto_first_child_for_byte(offset).is_some() {}
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let node_range = cursor.node().byte_range();
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if node_range.to_inclusive().contains(&offset) && node_range.len() < range.len() {
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range = node_range;
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scope = Some(LanguageScope {
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language: layer.language.clone(),
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override_id: layer.override_id(offset, &self.text),
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});
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}
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}
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scope
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}
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pub fn surrounding_word<T: ToOffset>(&self, start: T) -> (Range<usize>, Option<CharKind>) {
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