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Track open buffers when handling sync requests

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When a host sends a buffer to a guest for the first time, they record that
they have done so in a set tied to that guest's peer id. When the guest
reconnects and syncs buffers, they do so under a different peer id, so we
need to be sure we track which buffers we have sent them to avoid sending
them the same buffer twice, which violates the guest's assumptions.
This commit is contained in:
Nathan Sobo 2023-01-02 20:12:00 -07:00
parent 74843493f4
commit a6ffcdd0cf
3 changed files with 29 additions and 14 deletions
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11
crates/gpui/src/executor.rs
View file

@ -4,7 +4,7 @@ use futures::channel::mpsc;
use smol::{channel, prelude::*, Executor};
use std::{
any::Any,
fmt::{self, Display, Write as _},
fmt::{self, Display},
marker::PhantomData,
mem,
pin::Pin,
@ -17,8 +17,7 @@ use std::{
use crate::{
platform::{self, Dispatcher},
util::{self, CwdBacktrace},
MutableAppContext,
util, MutableAppContext,
};
pub enum Foreground {
@ -549,6 +548,8 @@ impl Future for Timer {
#[cfg(any(test, feature = "test-support"))]
impl DeterministicState {
fn push_to_history(&mut self, event: ExecutorEvent) {
use std::fmt::Write as _;
self.poll_history.push(event);
if let Some(prev_history) = &self.previous_poll_history {
let ix = self.poll_history.len() - 1;
@ -560,7 +561,7 @@ impl DeterministicState {
"current runnable backtrace:\n{:?}",
self.runnable_backtraces.get_mut(&event.id()).map(|trace| {
trace.resolve();
CwdBacktrace(trace)
util::CwdBacktrace(trace)
})
)
.unwrap();
@ -571,7 +572,7 @@ impl DeterministicState {
.get_mut(&prev_event.id())
.map(|trace| {
trace.resolve();
CwdBacktrace(trace)
util::CwdBacktrace(trace)
})
)
.unwrap();