Undo making project optional on stored follower states

Following works without a project, but following in unshared projects does
not need to be replicated to other participants.
This commit is contained in:
Max Brunsfeld 2023-09-28 14:21:44 -07:00
parent ce940da8e9
commit e9c1ad6acd
9 changed files with 47 additions and 93 deletions

View file

@ -1901,7 +1901,7 @@ async fn follow(
session
.db()
.await
.check_can_follow(room_id, project_id, leader_id, session.connection_id)
.check_room_participants(room_id, leader_id, session.connection_id)
.await?;
let mut response_payload = session
@ -1913,12 +1913,14 @@ async fn follow(
.retain(|view| view.leader_id != Some(follower_id.into()));
response.send(response_payload)?;
let room = session
.db()
.await
.follow(room_id, project_id, leader_id, follower_id)
.await?;
room_updated(&room, &session.peer);
if let Some(project_id) = project_id {
let room = session
.db()
.await
.follow(room_id, project_id, leader_id, follower_id)
.await?;
room_updated(&room, &session.peer);
}
Ok(())
}
@ -1935,19 +1937,21 @@ async fn unfollow(request: proto::Unfollow, session: Session) -> Result<()> {
session
.db()
.await
.check_can_unfollow(room_id, project_id, leader_id, session.connection_id)
.check_room_participants(room_id, leader_id, session.connection_id)
.await?;
session
.peer
.forward_send(session.connection_id, leader_id, request)?;
let room = session
.db()
.await
.unfollow(room_id, project_id, leader_id, follower_id)
.await?;
room_updated(&room, &session.peer);
if let Some(project_id) = project_id {
let room = session
.db()
.await
.unfollow(room_id, project_id, leader_id, follower_id)
.await?;
room_updated(&room, &session.peer);
}
Ok(())
}